Derivative Shortcut Tricks #3 #shorts #dineshsirlivestudy

y=X^x
diff. w.r.t. x
dy/dx= X^x (1+log x)
😊❤

Thanks sir

Keh do naa palas 2

Let y = sinx^sinx
Taking log both sides
log y = sinx log(sinx)
Applying product rule
1/y( dy/dx) = sinx( 1/sinx)cosx + log(sinx)cosx
Cosx is common taking outside
dy/dx = y[ 1 + log(sinx)] cosx
dy/dx = sinx^sinx [ 1 + log(sinx)] cosx

Jisko bhi nahi samjh aaya to jakar padhai kar lo😂

Or commerce or science khelna band karo

Taking log both side bro

Take log on both sides to solve for boards 😅

Bhai sidhe dono side log lelo

Log y= sin x log sin x
¹/y dy/dx=sinx (¹/sinx) cosx+log(sinx) cosx
¹/y dy/dx=cosx+log(sinx)cosx
¹/y dy/dx=cosx(1+log(sinx))
dy/dx=sinx^sinx cosx(1+log(sinx))

Taking log on both sides ❤❤❤

PCB students attendence here ☠️☠️

Your accent give vibe of tmkoc❤

Cet - cut short enjoying tricks

Sir it's really the easiest trick..😁
Thank you

Awesome

"Ruk Ruk Ruk" , had me cracking up 😂

Pr apun toh kal board ke exam ke liye kr rha 😅❤😊

"Hogya kya??"
"Ruk ruk ruk"
Litreally impatient me and my patient teacher😂

Qnswer 0 hoga

Sir board mein bhi 75 percentage chaiye hoti hain

sir pehi baar apki trick se zyada easy .......hai ki hum uska derivative hi nikaal le

F(x)^g(x) formula he

Cosx ho to😢

Dinesh+kartik
Nice combination😂❤

Both side take log
And apply log property
After that apply differentiation product formula

Karthik bhaiyya be like --- aata mla nay solve karaych bas zal

Ye to aaram se chain rule se hojayega.

cos x is with log sinx not outside the bracket.

Board

🔥🔥

(Cos )^sinx ka kijiye to aaise

Sir was just about to hug kranti if the question doesn't approch....at beginning 💀

Using product rules solve

Sir my to dekh ker hi ker diya toda sa time lga 😅😅😅😅.....👍👍👍

Bal.......

Thank sir ❤

For boards
Take log on both sides
Log(y)=sinx•log(sinx)
Differentiating w.r.t.x
1/y•dy/dx=sinx(d(log(sinx)/dx) + log(sinx)d(sinx)/dx
Dy/dx=y(cosx+cosx•log(sinx)
dy/dx=y(cosx(1+log(sinx)
dy/dx=sinx^sinx(cosx(1+log(sinx)

Sir toh Munna Bhai ki voice main padha rahe hain

You may use x^x formula that's x^x(1+logx) and just derivative of sinx
It's not trick it's simple mind calculation

X^x ka formula hai sir aapne aarambh mein bataya tha sirji 😊

Ye shortcut nahi hai answer hai ye

👏🏻👏🏻👏🏻 thank you sir

Kyu rata rhe ho bey not good method of teaching

Amazing sir

Impressive trick Sir

Logarithmic differentiation 😂😂😂 halwa hai 💀💀

Or shortcut dhyan na rahe, toh simple method he v1^v2 = e^v2lnv1 and derivate

Amazing 🎉🎉🎉🎉

2 marks fix

Koi trick nahi hai ; dy/dx x^x = x^x(1+lnx). Sir just putted the value of x 😅😅😅

Find the second derivative of the function y = sin 𝑥
2
(log 𝑥)
2 solve this question ❓