Conservation of Momentum In Two Dimensions - 2D Elastic & Inelastic Collisions - Physics Problems

Very clear explanation, but I do see a problem with your example. You show the balls moving at right angles to each other after the collision. This is not possible when the masses are unequal. If you calculate the kinetic energy before and after the collision, you'll find that the kinetic energy is greater after the collision. This is impossible, even for an inelastic collision.

What if you are only given one angle and one speed vector? This doesn't work in that case

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Hi I'm malik Andrew from Nigeria I have a little problem on momentum and impulse

There's a clear error in the derivation. Look at KE before and after.
KE before = (1/2) * 5 * 6^2 = 90

KE after = (1/2)*5*(5.2)^2 + (1/2)*3*5^2 = 67.6 + 37.5 = 105.1 KE cannot be greater!

Also, a commenter said that the degree total was 90 and that could not be, because the masses were not equal.
Well, I don't think so. If the angles total to 90, then the collision is elastic irrespective of the masses.

I dont get how you can sub in the y value with the x value, towards 7min. Plz somebody explain 😭😭

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Hi. I have a really important question about this video and I would be really grateful if someone could help me!

From what I know, when a ball hits a ball with the condition that the vector of the collision is pointing from the center of the first ball to the center of the second one, than the direction if the ball, which is being hit, would be the same as the direction of first ball, because as mentioned, it is a “center to center” collision.

So I come to the conclusion that the case that is described in this video is possible, if the collision vector is not pointing at center of the second ball and so, we get different angles of the 2 balls, telling us the exact direction of each one. Am I missing something, or did I catch this right.

2. Question (I am really sorry😅)

If we have a different scenario, where you have to calculate the angles of the 2 balls after the collision, do the speed of the balls after the collision have to be constant? For example in air-hockey, the speeds are not constant because of low friction. So do I necessarily get different angles based on inconstant speeds? This is important for a project, so it really would help a lot if someone would help me…Thanks to you all!

why is it cos?

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Very difficult to understand 😢

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Is this elastic or inelastic collisions?

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It is solution for freshman for long periods

Hello I have loved your videos ever since I was a little undergrad. I did notice if you take your final velocities and plug them into the kinetic energy formula, energy is gained. Could you explain this?

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Its easier to solve it without calculating decimals

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Initial Ek (M1) = mv^2/2 = 5*6*6/2 = 90J
Final Ek (M1+M2) = M1V1^2/2 + M2V2^2/2 = 5*5.196*5.196/2 + 3*4.99*4.99/2 = 67.49 + 37.35 = 104.84J
Final Ek- Initial Ek - 104.84J - 90J = +14.84J - 💪Free energy 💪

Im my book the give you the initial velocities and a final speed of one of them and ask for the angles and the final velicity of the other one and calculators ARE NOT allowed and im losing my sanity trying to calculate and solve the equation because they have sin and cos all over the place


How do i get around that