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Thanks ji
ОтветитьExcellent in your explanations sir. Very useful for my preparations. Thank you sir.
ОтветитьEnglish medium available
ОтветитьNo wonder if some of these questions may come in next group 1!!!!!!!
ОтветитьWonderful explanation sir....
ОтветитьClass is super sir, kindly share the fees structure.when will you start new csat batch ?
ОтветитьSuperb..
ОтветитьI need the UPSC questions papers sir...
ОтветитьSir screen theliva show agala sir
Ответить945 ÷ 4 remainder 1 eppid varum
ОтветитьVery Excellent Teacher but going Fast,
Your Hard work is Amazing 👏
For the 49th question ..
One can do the actual calculation that is 10000000000÷7
One can observe that the remainder cycle repeats every 6th time ... Means.. finding the remainder of the rest 4th cycle gives the actual remainder that is 4 which falls on Thursday
🎉❤
ОтветитьIt's very useful thank u soo much sir
ОтветитьSir, 10th question if we take 108/9=12& diff is 7 and 7 is one of the option
ОтветитьHow sir 945÷4 is 1 ... Sir can you please explain it how?
ОтветитьVery good explanation.
Thank you very much sir
Sir 14 question p=7 and c=10 how its satisfies the first condition can u explain me
ОтветитьThank you so much sir
Ответить29 question.ans.946?
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